Calculate The Ph Of A 0.160 M Glycine Hg Solution

Chemistry Calculator

Calculate the pH of a 0.160 M Glycine HG Solution

Use this interactive calculator to estimate the pH of a protonated glycine solution, often represented as glycine HG or the fully protonated glycine acid form. The default chemistry model uses the first acid dissociation of glycine and solves the equilibrium exactly with the quadratic equation.

Default concentration
0.160 M
Default pKa1
2.34
Model
Exact weak acid

How to calculate the pH of a 0.160 M glycine HG solution

If you need to calculate the pH of a 0.160 M glycine HG solution, the key idea is to identify what chemical species is actually present in water. In many acid-base problems, glycine is treated as an amino acid with multiple protonation states. When written in a form such as glycine HG, the intent is commonly the protonated acidic form of glycine, meaning the species donates a proton to water and behaves like a weak acid. For pH work, that means we focus primarily on the first acid dissociation constant of glycine, often reported near pKa1 = 2.34 at 25 degrees C.

Glycine is amphoteric, so it can behave as both an acid and a base. However, if the problem specifically asks for the pH of a glycine HG solution at a known molarity, the most practical introductory approach is to model the protonated form as a weak monoprotic acid. This works well because the first dissociation dominates the hydrogen ion concentration in an acidic solution. The result is a pH that is much lower than neutral water but still not as low as a strong acid of the same concentration.

Step 1: Write the acid dissociation equilibrium

Treat protonated glycine as a weak acid, represented here as HA. In water:

HA ⇌ H+ + A-

For a 0.160 M starting concentration, the equilibrium setup is:

Initial: [HA] = 0.160, [H+] = 0, [A-] = 0
Change: -x, +x, +x
Equilibrium: [HA] = 0.160 – x, [H+] = x, [A-] = x

The acid dissociation expression is:

Ka = [H+][A-] / [HA] = x² / (0.160 – x)

For glycine, pKa1 is often taken as 2.34, so:

Ka = 10^-2.34 ≈ 0.00457

Step 2: Solve using the exact quadratic method

Substitute the concentration and Ka into the equilibrium expression:

0.00457 = x² / (0.160 – x)

Rearranging:

x² + 0.00457x – 0.0007312 = 0

Solving the quadratic gives:

x ≈ 0.0249 M

Since x = [H+], the pH is:

pH = -log10(0.0249) ≈ 1.60
Final answer: the pH of a 0.160 M glycine HG solution is approximately 1.60 when glycine HG is treated as the protonated weak acid form and pKa1 = 2.34 at 25 degrees C.

Why this result makes chemical sense

A pH near 1.60 may initially seem surprisingly low for an amino acid solution, but it is reasonable when the molecule is supplied in its acidic protonated form at relatively high concentration. Glycine itself is not a strong acid, yet at 0.160 M there is enough dissolved acid species that the equilibrium still generates a substantial hydrogen ion concentration. Because Ka is about 4.57 × 10-3, the acid is weak but not extremely weak. This produces measurable dissociation and a strongly acidic solution.

It is also helpful to compare the result with a hypothetical strong acid of the same concentration. A 0.160 M strong monoprotic acid would have [H+] = 0.160 M and pH about 0.80. Your glycine HG solution is less acidic than that because the acid dissociates only partially. That difference, nearly 0.8 pH units, reflects weak-acid equilibrium behavior.

Approximation versus exact solution

In many general chemistry courses, students first estimate weak-acid pH using the shortcut:

[H+] ≈ √(Ka × C)

Plugging in glycine values:

[H+] ≈ √(0.00457 × 0.160) ≈ 0.0270 M
pH ≈ 1.57

This approximation is close, but not exact. The reason is that the approximation assumes x is very small relative to the starting concentration. Here, x is around 0.025 M, which is more than 15% of 0.160 M, so the small-x assumption is not ideal. That is why the exact quadratic result, about pH 1.60, is more defensible and should be preferred when accuracy matters.

Method Hydrogen ion concentration [H+] Calculated pH Comment
Exact quadratic 0.0249 M 1.60 Best routine choice for this concentration
Weak-acid approximation 0.0270 M 1.57 Slightly overestimates acidity
Strong acid assumption 0.160 M 0.80 Not chemically valid for glycine HG

Important acid-base data for glycine

Glycine has two commonly cited dissociation steps because it contains both an amino group and a carboxyl group. Typical 25 degrees C values used in instruction are approximately pKa1 = 2.34 and pKa2 = 9.60. The isoelectric point is near 5.97. These values can vary slightly by source, ionic strength, and temperature, but they are standard enough for most educational calculations.

Property Typical value Interpretation
pKa1 2.34 Loss of the first proton from the acidic glycine form
Ka1 4.57 × 10-3 Moderately weak acid behavior in water
pKa2 9.60 Further deprotonation involving the ammonium group
Isoelectric point 5.97 Net average charge is near zero at this pH

When the problem statement can be confusing

Chemistry notation is not always perfectly standardized across classes, textbooks, software tools, or instructor handouts. The phrase “glycine HG” can be interpreted in different ways if no explicit structure is supplied. In many contexts, however, the problem means the acidic protonated glycine species. If your teacher or textbook uses a different notation, make sure to verify whether the species is:

  • fully protonated glycine acting as a weak acid,
  • neutral zwitterionic glycine in water,
  • a glycine salt such as glycinate sodium, or
  • a metal complex or another ligand form not covered by the simple weak-acid model.

If the intended species were instead a zwitterion or a buffer mixture, the pH calculation would be different. The solution method always depends on what form of glycine is present initially.

Detailed calculation workflow for students

  1. Identify the species as the acidic form of glycine.
  2. Use the first dissociation constant, not the second one.
  3. Write the ICE table with starting concentration 0.160 M.
  4. Convert pKa1 to Ka using Ka = 10-pKa.
  5. Substitute into Ka = x² / (C – x).
  6. Solve the quadratic exactly.
  7. Set x equal to [H+].
  8. Compute pH = -log10[H+].
  9. Report the result with appropriate significant figures, typically pH ≈ 1.60.

Common mistakes to avoid

  • Using pKa2 instead of pKa1: the first dissociation controls the acidic solution pH.
  • Treating glycine HG as a strong acid: this gives a pH that is far too low.
  • Applying the small-x approximation without checking: here the approximation is usable but not ideal.
  • Ignoring concentration units: molarity must be in mol/L for the equilibrium setup used here.
  • Rounding too early: keep extra digits until the final pH step.

How concentration affects the pH

As the concentration of protonated glycine increases, the pH decreases, but not in the same simple one-to-one way that a strong acid does. For weak acids, equilibrium shifts according to both concentration and Ka. At lower concentrations, the fraction dissociated tends to be larger. At higher concentrations, the fraction dissociated tends to be smaller, even if the absolute hydrogen ion concentration rises.

For example, if glycine HG remained characterized by the same pKa1 value, a 0.010 M solution would have a significantly higher pH than a 0.160 M solution. This relationship is exactly why a chart is useful: it shows how hydrogen ion concentration, percent dissociation, and pH change together as you move away from the default concentration.

Reference links from authoritative sources

For deeper study of acid-base chemistry, equilibrium methods, and amino acid properties, consult these high-quality references:

Bottom line

To calculate the pH of a 0.160 M glycine HG solution, model glycine HG as the protonated weak-acid form of glycine, use pKa1 = 2.34, convert to Ka ≈ 0.00457, and solve the weak-acid equilibrium. The exact quadratic solution gives [H+] ≈ 0.0249 M and pH ≈ 1.60. If you use the weak-acid shortcut, you will get about pH 1.57, which is close but slightly more acidic than the exact answer.

For coursework, lab preparation, or study review, the safest response is to state your assumptions explicitly: “Assuming glycine HG refers to the protonated acidic form of glycine in water at 25 degrees C, the pH of a 0.160 M solution is approximately 1.60.” That sentence communicates both the chemistry and the reasoning behind the numerical result.

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