Calculate The Ph Of A 0.14 M Solution Of Diethylamine

Calculate the pH of a 0.14 M Solution of Diethylamine

Use this premium chemistry calculator to determine the pH, pOH, hydroxide concentration, and conjugate acid concentration for an aqueous diethylamine solution. The default setup is 0.14 M diethylamine at 25 degrees Celsius with a standard literature Kb value, but you can adjust the inputs for study, lab checking, and exam practice.

Weak Base Equilibrium Quadratic-Solution Ready Interactive Chart

Calculator

Default example: calculate the pH of a 0.14 M solution of diethylamine using Kb = 9.6 × 10-4.
Enter values and click Calculate pH to see the full equilibrium solution.

Equilibrium Visualization

This chart compares the starting diethylamine concentration with the equilibrium concentrations of unreacted base, hydroxide ion, and diethylammonium ion after the weak-base reaction reaches equilibrium.

How to calculate the pH of a 0.14 M solution of diethylamine

To calculate the pH of a 0.14 M solution of diethylamine, you treat diethylamine as a weak Brønsted base. Unlike a strong base such as sodium hydroxide, diethylamine does not ionize completely in water. Instead, only a fraction of the dissolved molecules accept a proton from water and generate hydroxide ions. That equilibrium behavior is the key reason this problem requires a weak-base calculation rather than a direct concentration-to-pH conversion.

Diethylamine, often written as (C2H5)2NH, reacts with water according to this equilibrium:

(C2H5)2NH + H2O ⇌ (C2H5)2NH2+ + OH

The equilibrium is described by the base dissociation constant, Kb. A commonly used room-temperature value for diethylamine is approximately 9.6 × 10-4, although exact values can differ slightly among references and temperatures. Once you know the initial concentration and Kb, the path to pH is straightforward: solve for hydroxide concentration, compute pOH, and then convert pOH to pH.

Step-by-step setup

  1. Write the balanced weak-base reaction in water.
  2. Set up an ICE table: Initial, Change, Equilibrium.
  3. Let x equal the hydroxide concentration formed at equilibrium.
  4. Substitute into the Kb expression.
  5. Solve for x exactly with the quadratic formula or approximately with the weak-base shortcut.
  6. Use pOH = -log[OH].
  7. Use pH = 14.00 – pOH at 25 degrees Celsius.

ICE table for 0.14 M diethylamine

If the starting concentration is 0.14 M and no hydroxide or conjugate acid is added initially, the ICE table becomes:

  • Initial: [Base] = 0.14, [BH+] = 0, [OH] = 0
  • Change: [Base] = -x, [BH+] = +x, [OH] = +x
  • Equilibrium: [Base] = 0.14 – x, [BH+] = x, [OH] = x

The base dissociation expression is:

Kb = [BH+][OH] / [Base] = x2 / (0.14 – x)

Using Kb = 9.6 × 10-4:

9.6 × 10-4 = x2 / (0.14 – x)

You can solve this exactly:

x2 + (9.6 × 10-4)x – (1.344 × 10-4) = 0

The physically meaningful root gives x ≈ 0.01112 M. Since x is the hydroxide concentration, [OH] ≈ 0.01112 M.

Now calculate pOH:

pOH = -log(0.01112) ≈ 1.954

Then convert to pH:

pH = 14.00 – 1.954 = 12.046

Final answer: the pH of a 0.14 M solution of diethylamine is about 12.05 at 25 degrees Celsius when Kb = 9.6 × 10-4.

Why this pH is basic but not as high as a strong base

Students often wonder why 0.14 M diethylamine does not produce a pH as high as 0.14 M sodium hydroxide. The reason is dissociation strength. Sodium hydroxide dissociates essentially completely, so the hydroxide concentration is nearly 0.14 M. Diethylamine is weak, so only a modest fraction converts into hydroxide ions. That partial proton-accepting behavior lowers the final [OH] and therefore lowers the pH relative to a strong base of equal formal concentration.

Solution Formal concentration Assumed dissociation behavior Approximate [OH] Approximate pH at 25 degrees Celsius
Diethylamine 0.14 M Weak base, partial reaction with water 0.0111 M 12.05
Sodium hydroxide 0.14 M Strong base, nearly complete dissociation 0.14 M 13.15

This comparison makes the chemistry intuitive. Both solutions start at the same formal molarity, but their proton-accepting power in water differs greatly because one is weak and one is strong. Therefore, molarity alone never tells the full pH story for weak electrolytes.

Approximation method versus exact quadratic method

For many weak acid and weak base problems, chemists use the approximation:

x ≈ √(Kb × C)

Here, C is the initial base concentration. For diethylamine:

x ≈ √[(9.6 × 10-4)(0.14)] = √(1.344 × 10-4) ≈ 0.01159 M

This gives a pOH around 1.936 and a pH around 12.064. That is very close to the exact quadratic answer. The difference is small because x is still much smaller than the starting concentration, although not tiny. If you need the most defensible answer for lab work, graded homework, or a chemistry calculator, the exact quadratic solution is better.

Method Equation used [OH] result pH result Comment
Exact quadratic x = [-Kb + √(Kb2 + 4KbC)] / 2 0.01112 M 12.046 Best for calculator-grade accuracy
Approximation x ≈ √(KbC) 0.01159 M 12.064 Fast and usually acceptable in classwork

What does the percent ionization tell you?

Another useful quantity is the percent ionization, which tells you what fraction of the original diethylamine actually reacts with water. It is calculated as:

Percent ionization = ([OH] / initial concentration) × 100

Using the exact result:

(0.01112 / 0.14) × 100 ≈ 7.94%

That means just under 8% of the diethylamine molecules are protonated at equilibrium under these conditions. This is entirely consistent with weak-base behavior: noticeable ionization, but far from complete dissociation.

Common mistakes when solving this problem

  • Using pH = -log(0.14): this is wrong because 0.14 M is the base concentration, not the hydrogen ion concentration.
  • Treating diethylamine as a strong base: weak bases require an equilibrium calculation.
  • Forgetting to calculate pOH first: bases produce hydroxide, so you usually find pOH before converting to pH.
  • Using Ka instead of Kb: diethylamine is a base, so Kb is the relevant constant unless you convert from the conjugate acid data.
  • Ignoring temperature: pH and equilibrium constants vary with temperature, although 25 degrees Celsius is standard for textbook problems.

How concentration affects the pH of diethylamine solutions

As the formal concentration of diethylamine increases, the hydroxide concentration also rises, but not in a perfectly linear way because the system is controlled by equilibrium. Weak bases tend to show a pH increase with concentration, but the exact change depends on both the concentration and Kb. The stronger the base, the more readily it forms hydroxide ions.

Below are representative values using Kb = 9.6 × 10-4 and the exact weak-base equation:

Diethylamine concentration Calculated [OH] pOH pH
0.010 M 0.00266 M 2.575 11.425
0.050 M 0.00646 M 2.190 11.810
0.140 M 0.01112 M 1.954 12.046
0.500 M 0.02146 M 1.668 12.332

This trend shows why concentration matters, but also why weak-base calculations are not the same as strong-base calculations. Even at 0.500 M, the pH is still far below what a 0.500 M strong base would generate.

Real-world context for diethylamine in chemistry

Diethylamine is an organic amine and a common example in acid-base chemistry because it is basic, water-reactive, and structurally simple enough to illustrate weak-base equilibrium behavior. Organic amines are relevant in synthesis, pharmaceuticals, analytical chemistry, and industrial processes. In introductory and general chemistry, they also serve as a bridge between pure equilibrium mathematics and real molecular behavior.

Because diethylamine has an alkyl-substituted nitrogen, it has greater electron density at nitrogen than ammonia, which tends to increase basicity in aqueous solution. That is one reason amines are often stronger bases than ammonia, although solvation and molecular structure can complicate exact comparisons.

Authoritative references and further reading

If you want to verify pH conventions, equilibrium fundamentals, and laboratory handling information, these references are useful:

Final takeaway

To calculate the pH of a 0.14 M solution of diethylamine, you must use weak-base equilibrium rather than assume complete ionization. Start with the reaction of diethylamine and water, define x as the hydroxide concentration formed, and solve the Kb expression. With Kb = 9.6 × 10-4, the exact calculation gives [OH] ≈ 0.01112 M, pOH ≈ 1.954, and therefore pH ≈ 12.05.

That result is chemically sensible: diethylamine is basic enough to produce a strongly basic solution, but because it is still a weak base, the pH remains lower than that of an equally concentrated strong base. If you are studying for exams, checking homework, or building intuition in equilibrium chemistry, this is a classic and very useful problem type to master.

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