Calculate The Ph Of 0.10M Ammonium Bromide Nh4Br Solution

Calculate the pH of 0.10 M Ammonium Bromide NH4Br Solution

Use this premium calculator to find the pH of an ammonium bromide solution by treating NH4+ as a weak acid and Br- as a spectator ion. The default values are set for a 0.10 M NH4Br solution at 25 degrees Celsius.

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Default setup: 0.10 M NH4Br, Kb of NH3 = 1.8 × 10^-5. Click Calculate to see pH, Ka, [H+], [OH-], and percent ionization.

Expert Guide: How to Calculate the pH of 0.10 M Ammonium Bromide NH4Br Solution

To calculate the pH of 0.10 M ammonium bromide, you need to recognize what happens when the salt dissolves in water. NH4Br is made from ammonium ion, NH4+, and bromide ion, Br-. Bromide is the conjugate base of a strong acid, hydrobromic acid, so it does not significantly affect pH in water. Ammonium, however, is the conjugate acid of the weak base ammonia, NH3. That means NH4+ can donate a proton to water and generate hydronium ions, making the solution acidic.

The most important idea is that NH4Br is not treated like a neutral salt such as sodium chloride. Instead, once it dissolves, the chemistry is controlled by the weak acid equilibrium of ammonium:

NH4+ + H2O ⇌ NH3 + H3O+

Because hydronium ions are formed, the pH falls below 7. For a 0.10 M solution at 25 degrees Celsius, using the commonly accepted base dissociation constant for ammonia, Kb = 1.8 × 10^-5, the conjugate acid constant for ammonium is:

Ka = Kw / Kb = (1.0 × 10^-14) / (1.8 × 10^-5) = 5.56 × 10^-10

Then, for a weak acid with initial concentration C, the hydronium concentration can be estimated by the weak acid approximation:

[H+] ≈ √(Ka × C)

Substituting C = 0.10 M gives:

[H+] ≈ √((5.56 × 10^-10)(0.10)) = √(5.56 × 10^-11) ≈ 7.46 × 10^-6 M

Now convert that to pH:

pH = -log[H+] = -log(7.46 × 10^-6) ≈ 5.13
Final answer for a 0.10 M NH4Br solution at 25 degrees Celsius: pH ≈ 5.13

Why NH4Br Makes an Acidic Solution

Students often make mistakes with salts because they try to memorize categories instead of analyzing the ions. A more reliable method is to break any salt into its cation and anion, then ask where each ion came from.

  • NH4+ comes from NH3, a weak base, so NH4+ is a weak acid.
  • Br- comes from HBr, a strong acid, so Br- is effectively neutral in water.
  • Net result: the solution is acidic because only NH4+ hydrolyzes appreciably.

This logic applies not just to ammonium bromide, but also to many other ammonium salts such as NH4Cl, NH4NO3, and NH4I. In each case, if the anion comes from a strong acid, the pH is mainly determined by the ammonium ion alone. That is why many ammonium salts produce pH values between about 4.5 and 6.5 depending on concentration.

Step by Step Method for Calculating pH of NH4Br

  1. Write the dissociation of the salt: NH4Br → NH4+ + Br-
  2. Identify the acid-base active ion: NH4+ is a weak acid, Br- is neutral.
  3. Convert Kb of NH3 to Ka of NH4+ if needed: Ka = Kw / Kb
  4. Write the weak acid equilibrium: NH4+ + H2O ⇌ NH3 + H3O+
  5. Use the weak acid expression: Ka = [NH3][H3O+] / [NH4+]
  6. Apply either the approximation or the quadratic equation.
  7. Find [H+], then calculate pH: pH = -log[H+]

Using the Approximation

When Ka is small and concentration is not extremely dilute, the change in concentration is much smaller than the initial concentration. In that case, for a weak acid HA with initial concentration C, the equilibrium gives:

Ka = x² / (C – x)

If x is very small relative to C, then C – x ≈ C, so:

x ≈ √(KaC)

For ammonium in a 0.10 M solution, this works very well because Ka is only 5.56 × 10^-10. The ionization is tiny, so the percent ionization is far below 5 percent and the approximation is justified.

Using the Exact Quadratic Equation

If you want a more rigorous answer, solve:

Ka = x² / (C – x)

which becomes:

x² + Kax – KaC = 0

The physically meaningful solution is:

x = (-Ka + √(Ka² + 4KaC)) / 2

For 0.10 M NH4Br, the exact value and the approximation are essentially identical to the precision normally expected in general chemistry, both giving a pH around 5.13.

Comparison Table: Relevant Acid-Base Constants

Species Constant Type Typical Value at 25 degrees Celsius Interpretation
NH3 Kb 1.8 × 10^-5 Ammonia is a weak base that only partially reacts with water.
NH4+ Ka 5.56 × 10^-10 Ammonium is a weak acid, so solutions of ammonium salts are acidic.
H2O Kw 1.0 × 10^-14 Links conjugate acid and base constants through Ka × Kb = Kw.
Br- Hydrolysis effect Negligible Bromide is the conjugate base of a strong acid and is treated as neutral.

How pH Changes with Concentration

One useful way to understand ammonium bromide is to compare pH at different molarities. As concentration increases, the total amount of NH4+ available to donate protons also increases, so the pH drops. However, the relationship is not linear because weak acid equilibria depend on the square root of concentration under the standard approximation.

NH4Br Concentration Calculated [H+] Approximate pH Percent Ionization of NH4+
0.001 M 7.46 × 10^-7 M 6.13 0.0746%
0.010 M 2.36 × 10^-6 M 5.63 0.0236%
0.10 M 7.46 × 10^-6 M 5.13 0.00746%
1.00 M 2.36 × 10^-5 M 4.63 0.00236%

Notice an interesting trend: the pH decreases as concentration rises, but the percent ionization actually gets smaller. That is a classic weak acid pattern. A more concentrated weak acid produces more hydronium overall, but a smaller fraction of the acid particles ionize.

Common Errors When Solving NH4Br pH Problems

  • Assuming the solution is neutral. It is not neutral because NH4+ is acidic.
  • Using Kb directly without conversion. If your data table gives Kb for NH3, convert it to Ka for NH4+ using Kw.
  • Treating Br- as basic. Bromide is the conjugate base of a strong acid, so its basicity is negligible in water.
  • Forgetting the logarithm sign. pH is the negative log of hydronium concentration.
  • Ignoring units and significant figures. Chemistry answers should reflect the precision of the given constants.

When the Simplified Formula Is Valid

The shortcut [H+] ≈ √(KaC) is very useful, but it rests on one assumption: the amount of dissociation x must be small relative to the starting concentration C. A standard check is the 5 percent rule. If x/C × 100 is less than about 5 percent, the approximation is normally acceptable. For 0.10 M NH4Br, the ionization fraction is tiny, so the assumption is excellent.

For 0.10 M NH4Br, percent ionization is only about 0.00746%, far below the 5% threshold.

Relation to Buffers and Biological Systems

The NH4+/NH3 conjugate pair is especially important in acid-base chemistry because it appears in buffers, environmental chemistry, and biochemistry. In wastewater treatment, soil chemistry, and aquatic systems, ammonium and ammonia interconvert depending on pH. At lower pH, ammonium is favored. At higher pH, ammonia becomes more significant. This is why a proper understanding of ammonium salt pH is useful beyond textbook exercises.

In a pure NH4Br solution, there is no significant amount of NH3 added initially, so the system is not a buffer. It is simply a weak acid solution derived from the ammonium ion. Once NH3 and NH4+ are both present in substantial amounts, then buffer equations such as Henderson-Hasselbalch become relevant.

Authoritative Reference Sources

If you want to verify acid-base constants or review aqueous equilibrium principles from trusted institutions, the following sources are excellent:

Worked Example Summary

Let us summarize the exact reasoning for the target problem, calculate the pH of 0.10 M ammonium bromide NH4Br solution.

  1. NH4Br dissociates completely into NH4+ and Br-.
  2. Br- is neutral because it comes from strong acid HBr.
  3. NH4+ is acidic because it is the conjugate acid of weak base NH3.
  4. Use Kb of NH3 = 1.8 × 10^-5.
  5. Convert to Ka of NH4+: Ka = 1.0 × 10^-14 / 1.8 × 10^-5 = 5.56 × 10^-10.
  6. Use [H+] ≈ √(KaC) = √((5.56 × 10^-10)(0.10)) = 7.46 × 10^-6 M.
  7. Compute pH = -log(7.46 × 10^-6) = 5.13.
Therefore, the pH of 0.10 M NH4Br solution is approximately 5.13 at 25 degrees Celsius.

Final Takeaway

The key to solving this problem is not memorizing a special formula for ammonium bromide. The key is understanding conjugate acid-base behavior. Once you identify NH4+ as a weak acid and Br- as neutral, the problem becomes a standard weak acid equilibrium calculation. For the common case of 0.10 M NH4Br, the answer is a mildly acidic pH of about 5.13. This result is chemically sensible, numerically consistent with accepted constants, and easy to reproduce using either the approximation method or the exact quadratic formula.

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