Calculate pH of the Solution Containing 0.1 M HCN and Ka
Use this interactive weak acid calculator to find the pH of hydrocyanic acid solutions using either the exact quadratic method or the common weak acid approximation. Enter the HCN concentration and Ka value, then visualize hydrogen ion concentration, pH, pKa, and percent dissociation instantly.
HCN pH Calculator
For a weak acid of initial concentration C and acid dissociation constant Ka:
Ka = x2 / (C – x), where x = [H+]
Exact solution: x = (-Ka + √(Ka2 + 4KaC)) / 2
Approximation when x ≪ C: x ≈ √(KaC), so pH ≈ -log10(√(KaC))
Results
How to Calculate pH of the Solution Containing 0.1 M HCN and Ka
If you need to calculate pH of the solution containing 0.1 M HCN and Ka, the key idea is that hydrocyanic acid, HCN, is a weak acid. Unlike strong acids such as HCl, weak acids do not dissociate completely in water. That means the hydrogen ion concentration is not equal to the starting acid concentration. Instead, you must use the acid dissociation constant, Ka, to determine how much HCN ionizes and then convert that value into pH.
HCN follows the equilibrium:
HCN(aq) ⇌ H+(aq) + CN–(aq)
The acid dissociation constant is defined as:
Ka = [H+][CN–] / [HCN]
For a starting concentration of 0.1 M HCN, you usually set up an ICE table and solve for the equilibrium concentration of H+. Because HCN is weak, the equilibrium hydrogen ion concentration will be much smaller than 0.1 M, and the resulting pH will be acidic but not nearly as low as a strong acid at the same concentration.
Step-by-Step Method
- Write the dissociation equation for HCN in water.
- Set the initial concentration of HCN to 0.1 M.
- Let the amount dissociated be x.
- At equilibrium, [H+] = x, [CN–] = x, and [HCN] = 0.1 – x.
- Substitute into the Ka expression: Ka = x2 / (0.1 – x).
- Solve for x using either the quadratic equation or the approximation x ≈ √(Ka × 0.1).
- Compute pH using pH = -log10(x).
Exact Example Using Ka = 4.9 × 10-10
Suppose your source gives the acid dissociation constant of HCN as 4.9 × 10-10. Let x represent the equilibrium hydrogen ion concentration. Then:
4.9 × 10-10 = x2 / (0.1 – x)
Rearranging gives:
x2 + (4.9 × 10-10)x – (4.9 × 10-11) = 0
Using the exact quadratic formula:
x = (-Ka + √(Ka2 + 4KaC)) / 2
Substitute C = 0.1 and Ka = 4.9 × 10-10:
[H+] ≈ 7.00 × 10-6 M
Then:
pH = -log10(7.00 × 10-6) ≈ 5.155
This is the standard result many students expect for a 0.1 M HCN solution when the Ka is around 4.9 × 10-10. The exact value changes slightly if your textbook, lab manual, or instructor uses a different Ka.
Approximation Method
Because HCN is weak, x is tiny compared with 0.1 M. That allows the common approximation:
0.1 – x ≈ 0.1
Then:
Ka ≈ x2 / 0.1
So:
x ≈ √(Ka × 0.1)
Using Ka = 4.9 × 10-10:
x ≈ √(4.9 × 10-11) ≈ 7.00 × 10-6 M
That produces almost the same pH as the exact method. In fact, for this case the approximation is excellent because the percent dissociation is very small.
What the Result Means Chemically
A pH near 5.15 tells you that a 0.1 M HCN solution is acidic, but only a very small fraction of HCN molecules release protons. The vast majority remain undissociated as HCN. This is exactly what you expect from a weak acid with a very small Ka. In practical terms, HCN is chemically weak in terms of proton donation, even though cyanide chemistry is still highly important and hazardous from a toxicological perspective.
Common Ka Values Reported for HCN
Different sources may report slightly different values for HCN because dissociation constants vary with temperature, ionic strength, and reference data conventions. The table below shows commonly cited ranges you may encounter in chemistry instruction.
| Parameter | Typical Value | Meaning | Impact on pH |
|---|---|---|---|
| Ka for HCN | 4.9 × 10^-10 | Common textbook value near room temperature | Gives pH about 5.155 at 0.1 M |
| Ka for HCN | 6.2 × 10^-10 | Alternative literature value used in some references | Gives slightly lower pH, about 5.104 at 0.1 M |
| pKa for HCN | 9.31 | Equivalent to Ka ≈ 4.9 × 10^-10 | Higher pKa means weaker acid |
| Percent dissociation at 0.1 M | About 0.007% | Only a tiny fraction ionizes | Supports use of weak acid approximation |
Comparison with Other Acids
One of the best ways to understand the pH of 0.1 M HCN is to compare it to other acids at the same analytical concentration. This shows how much acid strength influences pH. For example, strong acids dissociate nearly completely, while weak acids may dissociate less than one percent.
| Acid | Approximate Ka | 0.1 M pH | Relative Strength |
|---|---|---|---|
| HCl | Very large | 1.00 | Strong acid |
| HF | 6.8 × 10^-4 | 2.12 | Weak, but much stronger than HCN |
| CH3COOH | 1.8 × 10^-5 | 2.88 | Weak acid |
| HCN | 4.9 × 10^-10 | 5.16 | Very weak acid |
| H2CO3 first dissociation | 4.3 × 10^-7 | 3.68 | Weak acid, stronger than HCN |
Why the Weak Acid Approximation Works Here
The approximation x ≈ √(KaC) is valid when x is much smaller than the initial concentration C. A common classroom rule is that the approximation is acceptable if the percent dissociation is below 5%. For 0.1 M HCN, the dissociation is nowhere near that limit. The hydrogen ion concentration is only on the order of 10^-6 M, compared with an initial acid concentration of 10^-1 M. That means the drop in [HCN] is negligible for routine calculations.
Percent dissociation can be found using:
% dissociation = ([H+] / C) × 100
For this HCN example:
% dissociation ≈ (7.00 × 10-6 / 0.1) × 100 ≈ 0.007%
Since 0.007% is far below 5%, the approximation is extremely reliable.
How pKa Relates to Ka
Students often see both Ka and pKa and wonder which one to use. The relationship is:
pKa = -log10(Ka)
If Ka = 4.9 × 10^-10, then pKa is about 9.31. A larger pKa means a smaller Ka and therefore a weaker acid. Since HCN has a fairly high pKa, it is a weak proton donor in water. If your assignment gives pKa instead of Ka, simply convert it first:
Ka = 10-pKa
Frequent Mistakes When Solving HCN pH Problems
- Assuming HCN is a strong acid and setting [H+] = 0.1 M.
- Using pKa directly in the Ka equation without converting.
- Forgetting that HCN is monoprotic, so each dissociated molecule contributes one H+.
- Making a calculator input error with scientific notation.
- Using the approximation without checking whether dissociation is small enough.
- Rounding [H+] too early before computing pH.
When the Exact Method Is Better
Although the approximation works beautifully for 0.1 M HCN, the exact quadratic method is still the best all-purpose approach. It is especially useful when:
- The acid is not extremely weak.
- The concentration is very dilute.
- Your instructor requests an exact answer.
- You want to compare exact and approximate methods.
- You are building a chemistry calculator or lab spreadsheet.
Practical Interpretation of the pH Result
For most educational chemistry contexts, a pH around 5.1 to 5.2 is the expected answer for a 0.1 M HCN solution. The exact decimal depends on the Ka value chosen. This means the solution is acidic, but much less acidic than a strong acid at the same concentration. Because HCN ionizes only slightly, the conjugate base CN– remains at a very low equilibrium concentration in pure HCN solution compared with the undissociated acid.
Authoritative Chemistry and Safety References
For deeper reading, consult these authoritative sources:
- U.S. Environmental Protection Agency: Cyanide
- CDC ATSDR Toxic Substances Portal: Cyanide FAQ
- University of Wisconsin Chemistry: Acid-Base Equilibria
Final Takeaway
To calculate pH of the solution containing 0.1 M HCN and Ka, treat HCN as a weak acid and solve the equilibrium expression. With Ka = 4.9 × 10^-10, the equilibrium hydrogen ion concentration is about 7.00 × 10^-6 M, giving a pH of about 5.155. The weak acid approximation also works very well because the percent dissociation is only about 0.007%. If a different Ka is given, simply substitute that value into the same equation and recalculate. This page does that automatically, making it easier to check homework, compare literature constants, and understand weak acid behavior more clearly.