Calculate PDF of Random Variable Cubed
Use this interactive calculator to find the probability density function of Y = X3. Choose a source distribution for X, enter its parameters, evaluate the transformed density at a target y value, and visualize the resulting PDF with a responsive chart.
Transformed Density Plot for Y = X³
The chart updates from your selected source distribution and parameter values. The density can spike near y = 0 because the derivative of x = ∛y becomes very large there.
How to Calculate the PDF of a Random Variable Cubed
When statisticians ask for the PDF of a transformed variable such as Y = X3, they are asking how the original probability density of X changes after every possible value is cubed. This is a classic problem in probability theory because transformations appear everywhere: in signal processing, reliability modeling, physical measurement scaling, and simulation studies. The good news is that the cube transformation is monotone on the real line, which makes it one of the cleaner nonlinear transformations to handle correctly.
The central idea is simple. If you know the density of X, and you define Y = g(X) = X3, then you can derive the density of Y using the change-of-variables rule. Since the cube function is one-to-one and strictly increasing over all real numbers, it has an inverse:
Inverse transformation: x = g-1(y) = ∛y
Derivative of inverse: dx/dy = 1 / (3(∛y)2) = 1 / (3|y|2/3) for y ≠ 0
General transformed density: fY(y) = fX(∛y) × |dx/dy| = fX(∛y) / (3|y|2/3) for y ≠ 0
This formula explains why the transformed density often becomes sharply peaked near zero. Even when the original density of X is smooth and finite near 0, dividing by 3|y|2/3 can create a very tall density around the origin. That does not mean anything is wrong. It simply reflects how a small interval around x = 0 gets compressed very strongly when you cube values close to zero.
Step-by-Step Method
- Start with the original random variable and identify its density fX(x).
- Define the transformation Y = X3.
- Find the inverse x = ∛y.
- Differentiate the inverse to get dx/dy = 1 / (3|y|2/3) for y ≠ 0.
- Substitute into the change-of-variables formula to obtain fY(y) = fX(∛y) / (3|y|2/3).
- Transform the support of X through the cube function. If X is supported on [a, b], then Y is supported on [a3, b3].
- Check behavior near y = 0. The formula may indicate a singularity there, especially if fX(0) is positive.
Why the Cube Transformation Is Easier Than Many Other Nonlinear Maps
The reason this problem is manageable is that the function x ↦ x3 is strictly increasing over the entire real line. For transformations like Y = X2, the inverse is not one-to-one on all real numbers, so the density calculation requires summing contributions from positive and negative roots. That additional branch structure makes square transformations more delicate. By contrast, the cube has a unique real inverse for every real y, so the transformed PDF comes directly from a single inverse branch.
Support Matters
One of the most common mistakes is forgetting to transform the support correctly. The formula for the density only applies where the transformed random variable can actually live. If X follows an exponential distribution, then X is nonnegative. Since cubing preserves nonnegativity, Y = X3 is also nonnegative, so the transformed PDF is zero for all y < 0. If X is uniform on [-2, 3], then Y is uniform only after applying the cube map to the support endpoints, but the resulting density in y is not itself uniform. Instead, Y has support [-8, 27] and a density that changes with y.
Distribution-Specific Formulas
1. Normal Distribution: X ~ N(μ, σ²)
If X is normal with mean μ and standard deviation σ, then
fX(x) = (1 / (σ√(2π))) exp(-(x – μ)² / (2σ²)).
Substitute x = ∛y into the general transformation rule:
fY(y) = [1 / (σ√(2π))] exp(-(∛y – μ)² / (2σ²)) / (3|y|2/3), for y ≠ 0.
If μ = 0 and σ = 1, the transformed density is symmetric around 0 because the original standard normal density is symmetric and the cube map preserves sign.
2. Uniform Distribution: X ~ U(a, b)
If X is uniform on [a, b], then fX(x) = 1 / (b – a) for a ≤ x ≤ b. Therefore,
fY(y) = 1 / [(b – a) 3|y|2/3] whenever ∛y lies in [a, b]. Equivalently, y must lie in [a3, b3]. Outside that interval, the density is zero.
This is an excellent example of how a uniform input does not generally produce a uniform output after a nonlinear transformation. Values near zero become much more concentrated because cubing compresses that region.
3. Exponential Distribution: X ~ Exp(λ)
For an exponential random variable with rate λ, the density is fX(x) = λe-λx for x ≥ 0. Since X cannot be negative, Y = X3 also cannot be negative. The transformed density becomes
fY(y) = λe-λ∛y / (3y2/3), for y > 0, and 0 for y < 0.
This distribution is especially right-skewed because the original exponential distribution is already right-skewed and the cube transformation exaggerates large positive values.
Comparison Table: Example PDF Values for Standard Normal X and Y = X³
The table below shows actual transformed density values for the case X ~ N(0, 1). These numbers are useful because they illustrate the central geometric effect of the cube map: the density becomes large near zero even though the original normal density is modest there.
| y value | x = ∛y | Standard normal fX(x) | Transformed fY(y) | Interpretation |
|---|---|---|---|---|
| -8 | -2.000 | 0.05399 | 0.00450 | Far in the tail, transformed density is small. |
| -1 | -1.000 | 0.24197 | 0.08066 | Moderate negative y maps to a moderate x. |
| -0.125 | -0.500 | 0.35207 | 0.46943 | Near zero, density rises sharply. |
| 1 | 1.000 | 0.24197 | 0.08066 | Symmetry matches the standard normal case. |
| 8 | 2.000 | 0.05399 | 0.00450 | Positive tail mirrors the negative tail. |
Comparison Table: Example PDF Values for X ~ Exp(1) and Y = X³
This second table uses the exponential distribution with λ = 1. It highlights how the transformed density becomes very large near positive zero and then decays as y grows.
| y value | x = ∛y | Exponential fX(x) | Transformed fY(y) | Observation |
|---|---|---|---|---|
| 0.001 | 0.100 | 0.90484 | 30.16135 | Strong concentration near 0 due to the Jacobian term. |
| 0.125 | 0.500 | 0.60653 | 0.80871 | Density still elevated, but much lower than extremely near zero. |
| 1 | 1.000 | 0.36788 | 0.12263 | At y = 1, the transformed density is moderate. |
| 8 | 2.000 | 0.13534 | 0.01128 | Tail density becomes small as y increases. |
| 27 | 3.000 | 0.04979 | 0.00184 | Large y corresponds to thin right tail probability. |
Practical Interpretation
Why would anyone cube a random variable in practice? Cubing shows up whenever a measurement represents volume, torque-related scaling, nonlinear physical response, or a re-expression designed to stretch tails and compress values near zero. In simulation work, researchers often transform variables to test whether estimation methods remain stable under skewness or nonlinear rescaling. In machine learning and signal processing, nonlinear transformations can be part of feature engineering or model diagnostics.
The transformed density tells you where the probability mass is concentrated after the map is applied. For Y = X3, the output scale expands large magnitudes and compresses values near zero. But because density is measured per unit of y, the compression near zero means the density can become quite large there. This is exactly what the Jacobian term captures.
Common Mistakes to Avoid
- Ignoring the absolute value in the derivative. The density formula always uses the absolute Jacobian, so you need |dx/dy|.
- Forgetting support restrictions. The transformed density is only valid on the cube of the original support.
- Confusing the CDF and PDF approaches. Both work, but the PDF method is faster when the transformation is one-to-one and differentiable.
- Assuming the transformed density stays finite at zero. Often it does not. A vertical spike can still be perfectly integrable.
- Mixing x-space and y-space values. Always compute the original density at x = ∛y, not at x = y.
When to Use the CDF Method Instead
If the transformation is not monotone, the cumulative distribution function method can be safer. For Y = X3, monotonicity means the direct PDF method is straightforward. But in more complicated transformations, deriving FY(y) first and then differentiating can help avoid missing inverse branches. That said, for the cube transformation, the inverse-based Jacobian method is standard and efficient.
Authoritative References for Further Study
For readers who want rigorous statistical background, these references are excellent starting points:
- NIST Engineering Statistics Handbook for practical probability and distribution guidance.
- Penn State STAT 414 Probability Theory for formal treatment of transformations of random variables.
- University of California, Berkeley Statistics for broad academic resources in probability and mathematical statistics.
Final Takeaway
To calculate the PDF of a random variable cubed, begin with the inverse transformation x = ∛y, compute the absolute derivative, and substitute into the original density. The universal formula for a one-to-one cube transform is
fY(y) = fX(∛y) / (3|y|2/3) for y ≠ 0, together with the correctly transformed support.
Once you understand that one formula, you can handle normal, uniform, exponential, and many other continuous distributions with confidence. Use the calculator above to verify examples quickly, inspect support changes, and visualize how cubing reshapes the density.