Calculate the pH of 0.075 M KOH
Use this premium calculator to determine pOH and pH for potassium hydroxide solutions, visualize how concentration affects alkalinity, and review the chemistry behind why 0.075 M KOH is a strongly basic solution.
KOH pH Calculator
Potassium hydroxide is a strong base, so it dissociates essentially completely in water. Enter the concentration, choose the temperature assumption for pKw, and calculate the solution pH instantly.
- For strong bases like KOH, [OH–] is approximately equal to the base molarity.
- At 25 C, pH + pOH = 14.00.
- Default example: 0.075 M KOH gives a pH of about 12.8751 at 25 C.
Concentration vs pH Chart
This chart compares the entered concentration with nearby KOH concentrations so you can see how rapidly pH changes on the logarithmic scale.
How to Calculate the pH of 0.075 M KOH
If you need to calculate the pH of 0.075 M KOH, the chemistry is straightforward because potassium hydroxide is a strong base. In aqueous solution, KOH dissociates almost completely into K+ and OH–. That means the hydroxide ion concentration is effectively equal to the stated molarity of the KOH solution, provided the solution is dilute enough for introductory chemistry assumptions to hold. For a 0.075 M solution, you can therefore set [OH–] = 0.075 M and solve for pOH first, then pH.
Since one formula unit of KOH produces one hydroxide ion, the stoichiometric relationship is 1:1. The next step uses the pOH equation:
Substitute 0.075 for the hydroxide concentration:
At 25 C, pH and pOH are related by the water ion-product expression:
So the pH becomes:
Why KOH Is Treated as a Strong Base
Strong bases are substances that ionize almost completely in water. Potassium hydroxide belongs in this category along with sodium hydroxide and lithium hydroxide. In practical pH calculations for standard classroom and laboratory concentrations, this means you do not need an equilibrium ICE table to estimate how much OH– is present. Instead, you assume complete dissociation and work directly from molarity.
This is the key reason the problem is easier than calculating the pH of a weak base such as ammonia. With a weak base, the concentration of OH– would have to be found using a base dissociation constant, Kb, because only part of the dissolved base reacts with water. With KOH, the dissociation is effectively complete, so the hydroxide concentration tracks directly with the amount of base dissolved.
Step by Step Method for 0.075 M KOH
- Identify KOH as a strong base.
- Write the dissociation: KOH -> K+ + OH–.
- Use the 1:1 relationship to set [OH–] = 0.075 M.
- Calculate pOH: pOH = -log(0.075) = 1.1249.
- At 25 C, calculate pH: 14.00 – 1.1249 = 12.8751.
- Round appropriately, often to 12.88.
That process is the standard textbook route. If your instructor asks for fewer significant figures, report 12.88. If your data are intended for analytical work, preserve more decimal places until the final rounding step.
Common Student Mistakes
- Using the concentration directly in the pH formula instead of the pOH formula. Because KOH is a base, you calculate pOH from [OH–] first.
- Forgetting complete dissociation. KOH is not treated as a weak base under normal general chemistry conditions.
- Using pH + pOH = 14 without checking temperature. The value 14.00 is correct specifically at 25 C.
- Entering 75 instead of 0.075 into the logarithm. The concentration must be in mol/L.
- Confusing molarity with moles. A value of 0.075 M means 0.075 moles per liter.
How Temperature Affects the Result
In many homework problems, the temperature is assumed to be 25 C, so pKw is taken as 14.00. However, pKw changes with temperature because the autoionization constant of water changes. That means the exact pH of the same hydroxide concentration can shift slightly as temperature changes, even though the hydroxide concentration itself remains the same in your simple strong-base model.
This is why the calculator above lets you choose a temperature assumption. If you hold [OH–] = 0.075 M but use a pKw smaller than 14.00, the calculated pH is slightly lower. This does not mean the solution became less basic in terms of hydroxide concentration. It means the neutral point of water itself has shifted.
| Temperature | Approximate pKw | pOH for 0.075 M OH– | Calculated pH |
|---|---|---|---|
| 10 C | 14.17 | 1.1249 | 13.0451 |
| 25 C | 14.00 | 1.1249 | 12.8751 |
| 30 C | 13.93 | 1.1249 | 12.8051 |
| 40 C | 13.83 | 1.1249 | 12.7051 |
| 50 C | 13.73 | 1.1249 | 12.6051 |
The values above are useful for comparison because they show that your logarithmic step, pOH = -log(0.075), stays the same, while the conversion to pH depends on temperature through pKw. For most classroom exercises, though, the accepted answer remains 12.88 at 25 C.
Comparison of KOH Concentrations and Their pH at 25 C
It also helps to compare 0.075 M KOH with nearby concentrations. Because pH is logarithmic, the relationship between concentration and pH is not linear. Doubling concentration does not double pH. Instead, it changes the pOH by a logarithmic amount. The table below illustrates this pattern for common KOH solution strengths at 25 C.
| KOH Concentration (M) | [OH–] (M) | pOH | pH at 25 C |
|---|---|---|---|
| 0.001 | 0.001 | 3.0000 | 11.0000 |
| 0.010 | 0.010 | 2.0000 | 12.0000 |
| 0.050 | 0.050 | 1.3010 | 12.6990 |
| 0.075 | 0.075 | 1.1249 | 12.8751 |
| 0.100 | 0.100 | 1.0000 | 13.0000 |
| 0.200 | 0.200 | 0.6990 | 13.3010 |
Notice how 0.075 M sits between 0.050 M and 0.100 M, producing a pH between 12.6990 and 13.0000. This makes intuitive sense and provides a quick check for whether your calculation is in the right range.
What 0.075 M Means in Practical Terms
A molarity of 0.075 M means there are 0.075 moles of KOH in each liter of solution. Because potassium hydroxide has a molar mass of about 56.11 g/mol, a 0.075 M solution corresponds to about 4.21 grams of KOH per liter if prepared ideally. In lab work, KOH is highly caustic and hygroscopic, so actual preparation should be carried out with proper personal protective equipment and good technique. Even relatively modest molarities can produce very high pH values and can cause chemical burns.
Why the Answer Is Not Simply 14
Students sometimes assume any strong base must have a pH of exactly 14. That is not correct. A pH of 14 corresponds to a specific hydroxide concentration of 1.0 M at 25 C under the idealized equation pOH = 0 and pH = 14. A 0.075 M solution is still strongly basic, but its hydroxide concentration is less than 1.0 M, so the pOH is greater than zero and the pH is below 14. The correct value, 12.8751, reflects a substantial but not maximal hydroxide concentration on the standard pH scale.
When Real Solutions May Deviate
In advanced chemistry, very concentrated or highly nonideal solutions may require activity corrections rather than using raw molarity alone. Instrument calibration, dissolved carbon dioxide, contamination, ionic strength, and temperature control can all affect measured pH. Nevertheless, for a standard general chemistry calculation asking for the pH of 0.075 M KOH, the complete dissociation assumption is the expected and correct method. The calculated answer of 12.88 is the academically accepted result at 25 C.
Reliable Reference Sources
For additional reading on pH, alkalinity, and water chemistry, consult authoritative sources such as the U.S. Environmental Protection Agency on pH, the U.S. Geological Survey water science overview of pH, and the National Institute of Standards and Technology guidance on pH standards. These sources explain pH measurement, why pH matters in aqueous systems, and how standards are maintained for analytical chemistry.
Quick Recap
- KOH is a strong base and dissociates completely.
- For 0.075 M KOH, [OH–] = 0.075 M.
- pOH = -log(0.075) = 1.1249.
- At 25 C, pH = 14.00 – 1.1249 = 12.8751.
- Rounded result: pH = 12.88.
If your assignment, lab prewrite, or exam question asks you to calculate the pH of 0.075 M KOH, this is the exact reasoning your instructor expects to see. State the dissociation, compute pOH from hydroxide concentration, convert to pH using the temperature-appropriate pKw, and report the final value with sensible rounding.